Pythagorean Theorem Proof

A B C 0 1
.5
Y-Coordinate .5
Length of Side A 0.7071067811865476
Length of Side B 0.7071067811865476
Length of Side C 1
Area of Triangle .25
Area of Inner Square 0
Area of Outer Square 1

The area of each triangle is ½ × ( A × B )

The area of the inner square is ( A - B )2

The area of the outer square is:

C2 = 4 × ½ × ( A × B ) + (A - B)2

C2 = 2AB + A2 - 2AB + B2

C2 = A2 + B2